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New Year Giveaway

Day 1,881, 20:33 Published in Philippines Philippines by Vincenzo Roque
This is a part of my series of articles in my New Year Giveaway. To know more, read this.

Let X be the answer to the twelfth question and let Y be the sum of the digits of X. Let Z = 3Y^2 + 21Y + 18. How many pythagorean triples (a,b,c) have a sum a + b + c less than or equal to Z?

Good luck!

Still Wishing you a Merry Christmas and a Happy New Year,

Vincenzo Roque
Proudly Pinoy


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